LOCAL VARIABLE

=========================================
public class test1{
public static void main(String args[]){
int x =10;
int y;
if(x > 5) y =0
System.out.println("y"+y);
}
}
==========================================
public class test2{
public static void main(String args[]){
int x =10;
int y;
if(x > 5) y =0
else y = 1;
System.out.println("y"+y);
}
}
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test1 says the variable is not initialised.
test2 works fine.
i dont know why???
pls helps........regards......Jaya Murugan

In the code:
public static void main(String args[]){
int x =10;
int y;
if(x > 5) y =0
System.out.println("y"+y);
}
The compiler determines that there is a logical path in which y is never initialized. In order for it to determine that y is always initailized for the particular value of x that is set, the compiler would have to actually execute the program. Obviously impossible, so it gives the warning.
Bill

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