question 3 on javaprepare

[may leung]

Hi all,
What gets printed when the following code is compiled and run with the following command -
java test 2
Select the one correct answer.

public class test {
public static void main(String args[]) {
Integer intObj=Integer.valueOf(args[args.length-1]);
int i = intObj.intValue();
if(args.length > 1)
System.out.println(i);
if(args.length > 0)
System.out.println(i - 1);
else
System.out.println(i - 2);
}
}

The ans is 1. Can anyone explain to me why?
Thanks!!!

[bill bozeman]

Step through the code.
1. You are getting the value of the first argument passed on the command line and passing it into an Integer object.
2. You take that value and return it as an int with intObj.intValue(). So i = 2.
3. You check to see if the length of args is greater than 1, which it is not since there is only one value ("2") passed in so length = 1.
4. You check to see if the length of args is greater than 0 which it is since a value was passed in, so you take i-1 which is 1
Bill

[may leung]

oh!!
I'm clear now
Thank you