I have a basic question:- 1.>int i=2147483648; The above code will generate the compile time error for the value being one more than the positive range.But.... 2.>int i=-(-2147483648); The above code will compile successfully.and the output will be '-2147483648'. Why does this things compiles b'coz after negating those minus signs the value is still out of int's range. Help me Golu Jain
Paul Anilprem
Enthuware Software Support
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Joined: Sep 23, 2000
Posts: 2912
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The reason is the range of signed types is not symetric. For. eg. int's range is -2^31 to 2^31-1. You can see that, it can store 1 negative number more than positive no. Now, at runtime when you negate the largest -ive no., it's positive value falls outside the range by 1. So, in effect you get the same negative number. HTH, Paul. ------------------ Get Certified, Guaranteed! (Now Revised for the new Pattern) www.enthuware.com/jqplus
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