# q from Jxam

Cristi Tudose

Ranch Hand

Posts: 53

posted 15 years ago

here is the q,answers and some explanations:

Given the following definition:

String s = null;

Which code fragment will cause an exception of type NullPointerException to be thrown.

##ans1##

if ((s != null) & (s.length()>0))

##ans2##

if ((s != null) && (s.length()>0))

##ans3##

if ((s != null) | (s.length()>0))

##ans4##

if ((s != null) | | (s.length()>0))

##ans5##

None of the above.

##correct##

1,2,3,4

i checked only 1,3,4 and even I compiled and saw that 2 is not a correct answer,i have doubt about the explanation-for answer 2

"Answer 1 must be fully evaluated. The LHS is true and so the RHS needs to be evaluated to ensure the entire expression is true. This is an AND operation, and if the LHS is true, then the RHS must be evaluated for the expression to be true.

Answer 2 is the same as above. Both sides need to be evaluated for an AND expression to be true (if the LHS is true, that is).."

am i missing something?

rgds,

cristi

Given the following definition:

String s = null;

Which code fragment will cause an exception of type NullPointerException to be thrown.

##ans1##

if ((s != null) & (s.length()>0))

##ans2##

if ((s != null) && (s.length()>0))

##ans3##

if ((s != null) | (s.length()>0))

##ans4##

if ((s != null) | | (s.length()>0))

##ans5##

None of the above.

##correct##

1,2,3,4

i checked only 1,3,4 and even I compiled and saw that 2 is not a correct answer,i have doubt about the explanation-for answer 2

"Answer 1 must be fully evaluated. The LHS is true and so the RHS needs to be evaluated to ensure the entire expression is true. This is an AND operation, and if the LHS is true, then the RHS must be evaluated for the expression to be true.

Answer 2 is the same as above. Both sides need to be evaluated for an AND expression to be true (if the LHS is true, that is).."

am i missing something?

rgds,

cristi

vadiraj vd

Ranch Hand

Posts: 68

posted 15 years ago

Hi Cristi,

You are missing the fact that '&&' is shortcircuit operator.

In short circuit operator evaluation, if the final result can be decided

by knowing the result of the first operand then the other operand

is NOT evaluated at all.

So the answer 2 is correct.

Hope this clears your doubt.

------------------

Regards

---------

vadiraj

*****************

There's a lot of I in J.

*****************

You are missing the fact that '&&' is shortcircuit operator.

In short circuit operator evaluation, if the final result can be decided

by knowing the result of the first operand then the other operand

is NOT evaluated at all.

So the answer 2 is correct.

Hope this clears your doubt.

------------------

Regards

---------

vadiraj

*****************

There's a lot of I in J.

*****************

Regards<BR>---------<BR>vadiraj<P><BR>*****************<BR>There's a lot of I in J.<BR>*****************

golu jain

Greenhorn

Posts: 19

Cristi Tudose

Ranch Hand

Posts: 53

posted 15 years ago

sorry vadiraj,u are right about theory

but here first part s!=null is avaluate to false

and false && X always evaluate false(without evaluate X)

so i think the correct answer should be 1,3,4

as golu jain observe too.

your opinion remain the same?

rgds,

cristi

but here first part s!=null is avaluate to false

and false && X always evaluate false(without evaluate X)

so i think the correct answer should be 1,3,4

as golu jain observe too.

your opinion remain the same?

rgds,

cristi

Originally posted by vadiraj vd:

Hi Cristi,

You are missing the fact that '&&' is shortcircuit operator.

In short circuit operator evaluation, if the final result can be decided

by knowing the result of the first operand then the other operand

is NOT evaluated at all.

So the answer 2 is correct.

Hope this clears your doubt.

Edy Yu

Ranch Hand

Posts: 264

posted 15 years ago

vadiraj vd:

(2) is

(2) is

**NOT</> the correct answer cus in this case, s.lenth() will never be called.**

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