look at the foll code : public class TestClass { public static void main (String args[ ] ) { int k = 1; int i = ++k + k++ + + k ; System.out.print(i+ " "+ k) ; } } what is the result?? i thought ++k makes it 2 then k++ keeps it at 2 and +k doesn't change its value( just makes it positive). so the result should be 2+2+2 = 6 i = 6; k = 2 But it is wrong!!!

Hi Shailendra.The answer will be 7,not 6.If we go over it... 1)Initially k=1; 2)++k will make k=2 since we are using a prefix operator.(as said by you).So currently the value of the expression is 2. 3)Now since there is a postfix operator in k++,the SAME VALUE of k will be used at that point in evaluating the expression.Thus now value is 2+2; 4)NOW k WILL BE INCREMENTED,because of the postfix operator.Thus now k=3; 5)Now to this expression,we are adding +k.Hence now we have value of expression as 2+2+3=7.This is assigned to i,hence i=7; Remember,at every point the CURRENT VALUE of the variable will be used when evaluating the expression. I hope i have been clear enough.

Udayan Naik<BR>Sun Certified Programmer for the Java 2 Platform

Shailendra Guggali
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Joined: Feb 01, 2001
Posts: 86

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Thanx uday

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