operators

[Sai Ram9]

what will happen if you compile/run this code?
public class Q10
{
public static void main(String[] args)
{
int i = 10;
int j = 10;
boolean b = false;
if(b = i ==j)
System.out.println("true");
else
System.out.println("false");
}
}
Answer says True... Please explain!

[Latha Kalaga]

Hi! Sai
In the statement
if(b = i ==j)
System.out.println("true");
else
System.out.println("false");

due to precedence of operators '==' has a higher precedence than '=' and so the statement can be read as b = (i==j);
i == j will be true and this gets assigned to the boolean b
hence the answer is 'true'.
Hope this helps.
Latha

Originally posted by Sai Ram9:
what will happen if you compile/run this code?
public class Q10
{
public static void main(String[] args)
{
int i = 10;
int j = 10;
boolean b = false;
if(b = i ==j)
System.out.println("true");
else
System.out.println("false");
}
}
Answer says True... Please explain!

[Sai Ram9]

Thanks latha. good and clear explanation.