reading array by console

[gul khan]

i have tried to wrote a class in which i tried to get input from user to populate an array but it results strange
class is
import java.io.*;
class arrayByConsole {
public static void main(String[] args) throws IOException {
BufferedInputStream bis =new BufferedInputStream(System.in);
int myValue=0;
byte[] Array =new byte[8];
System.out.println("Enter number and '10' to exit:");
do
{
Array[myValue]=(byte)bis.read();
myValue=myValue+1;
if (myValue>Array.length)
break;
}
while (Array[myValue-1]!=10);
for (int i=0;i<Array.length;i++){>
System.out.println(Array[i]);
}
}
}
Result is
Enter number and '10' to exit:
233410
50
51
51
52
49
48
13
10
Press any key to continue . . .
any comments and help will be appriciated

[Jane Griscti]

Hi Gul,
What you're seeing is the ASCII values for the digits '2,3,3,4,1,0' and CR and LF.
If you modify the code slightly you can see what's happening:

   for (int i=0; i < myValue; i++)
     System.out.println( i + ": " + Array[i] + "    " + (char)Array[i]);

The output is:

Enter number and '10' to exit:
233410
0: 50    2
1: 51    3
2: 51    3
3: 52    4
4: 49    1
5: 48    0
6: 13
7: 10

Elements 6 and 7 do not appear as characters.
Hope that helps.
------------------
Jane Griscti
Sun Certified Programmer for the Java� 2 Platform
[This message has been edited by Jane Griscti (edited February 20, 2001).]