a.) 3, 5, 18, 95, 1728,
3, 5, 18=(3*(5+1)), 95=(5*(18+1)),1728=(18+(95+1)) and hence you get 164225.
<b.) 7, 13, 56, 182, 3192, 33306, >
the alternate are in series..
7, 56=(7*(7+1)), 3192=(56*(56+1))..
the other alternate terms have the same relation too..
13, 182=(13*(13+1)), 33306=(182*(182+1))
hence from the first alt. series, missing term will be (3192*3193)
good, I finished the assignment!
[This message has been edited by Subramaniam Venkatesan (edited March 02, 2001).]