bitwise operators priority--from Jimmy's mock exam

Hi
I think the questions about operators in Jimmy are sort of tough. I was lost. See the examples plz.
I think &,|,^ are same in priority, and I can process from left to right. THe result: I got all questions below wrong.
I have given the output the explanation provided by the author, but it makes me more confused, when one evaluation is in
(b1(b2&(b3^b4))???
and another is in
(8|((9&10)^11)) ???
How come there is differences?
Thanks for the help.
CHris
public class Op
{
public static void main(String[] s){
boolean b1,b2,b3,b4;
b1=b2=b3=b4=true;
int m,n;
System.out.println(b1|b2&b3^b4?"true":"false");
//output : true (b1(b2&(b3^b4))???
m=8|9&10^11;//(8|((9&10)^11)) ???
System.out.println("m is "+m);
//output:11
n=7;
n<<=3;<br /> n=n&n+1|n+2^n+3;<br /> n>>=2;
System.out.println("n is "+n);
//output 14
}
}

Order of bitwise ops is &, then ^, then

Order of bitwise ops is &, then ^, then vertical bar

And, of course, + precedes even &

~ precedes & but follows arithmetic ops

Thanks. &^| sequence does work in all three cases. However, I read RHE about bitwise operator, my impression is the those three are equal. Even worse, my overall impression is the sequence has to be from left to right (after reading the discussion about short-circuit).
If possible, may I have a reference about this issue? I was lost in JLS.
Thanks a lot
Chris

In addition, the author give one answer as
(b1|(b2&(b3^b4))
though no difference in result, but now it is ^&|