This week's giveaway is in the Android forum. We're giving away four copies of Android Security Essentials Live Lessons and have Godfrey Nolan on-line! See this thread for details.

"JavaRanch, where the deer and the Certified play" - David O'Meara

Rahul Pawar
Ranch Hand

Joined: Mar 13, 2001
Posts: 38

posted

0

Originally posted by Cindy Glass: using java? or doing it by hand?

well actually i need to know how to convert decimals into octals and hexadecimals? thanks rahul

Rahul Pawar
Ranch Hand

Joined: Mar 13, 2001
Posts: 38

posted

0

Originally posted by Cindy Glass: OK The Integer class has a method valueOf(String 2, radix r); That takes the string representation of a number and converts it to the base that you feed in in r. So to convert 12345 to octal Integer x = Integer.valueOf(12345, 8); To convert to hex Integer x = Integer.valueOf(12345, 16);

thanks for ur reply but still i need to know how to do conversion without using valueOf() method ? thanks once again rahul

Cindy Glass
"The Hood"
Sheriff

Joined: Sep 29, 2000
Posts: 8521

posted

0

ok. The Integer class has two methods toHexString and toOctalString. String s1 = Integer.toHexString(12345); String s2 = Integer.toOctalString(12345);

Cindy Glass
"The Hood"
Sheriff

Joined: Sep 29, 2000
Posts: 8521

posted

0

Well, that was the first question. I guess you want to be able to do it by hand. (BTW I deleted my first reply - the syntax is WAY wrong). Normally I do it the hard way. To convert to octal Assuming a number less that 32,768 ____ ___ __ _ 4096 512 64 8 etc. Take the number in decimal and find out how may 4096's are in it. Put that number over the 4096 space. Take the remainder and find out how many 512's are in it, put that over the 512 space. Then find how many 64's are in the remainder, put it over the 64 space. The last number should be <=7 put it over the 8. Now it is in Octal. [This message has been edited by Cindy Glass (edited March 13, 2001).]

Rahul Pawar
Ranch Hand

Joined: Mar 13, 2001
Posts: 38

posted

0

thanks for ur immediate reply but still i am confuse about conversion . will u give me all the details along with ex. so that i can understand . thank u very much for ur reply rahul

Originally posted by Cindy Glass: Well, that was the first question. I guess you want to be able to do it by hand. (BTW I deleted my first reply - the syntax is WAY wrong). Normally I do it the hard way. To convert to octal Assuming a number less that 32,768 ____ ___ __ _ 4096 512 64 8 etc. Take the number in decimal and find out how may 4096's are in it. Put that number over the 4096 space. Take the remainder and find out how many 512's are in it, put that over the 512 space. Then find how many 64's are in the remainder, put it over the 64 space. The last number should be <=7 put it over the 8. Now it is in Octal. [This message has been edited by Cindy Glass (edited March 13, 2001).]

Rahul Pawar
Ranch Hand

Joined: Mar 13, 2001
Posts: 38

posted

0

can anybody help me out regarding conversion by hand from decimals to octals/ hexadecimals thanks in advance rahul

Hi Rahul, Are you familiar with binary conversions? As binary is,representing an integer to its base 2,an octal is representing an integer to its base 8 and hex is to the base 16. You can convert the number to an octal the same way you find the binary,except that you divide it by 8 instead of doing it by 2. IF you want a detailed explanation pl ask. Elizabeth.

Rahul Pawar
Ranch Hand

Joined: Mar 13, 2001
Posts: 38

posted

0

thanks Garath , thanks for ur reply . now my concept is clear . thansk for co-operation Rahul

If you know how to convert a floating point decimal number to a floating point binary and vise versa Albert

Originally posted by Elizabeth Jacob: Hi Rahul, Are you familiar with binary conversions? As binary is,representing an integer to its base 2,an octal is representing an integer to its base 8 and hex is to the base 16. You can convert the number to an octal the same way you find the binary,except that you divide it by 8 instead of doing it by 2. IF you want a detailed explanation pl ask. Elizabeth.