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output

 
Rahul Pawar
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class Q81{
public static void main(
String args[]){
System.out.print(
Double.isNaN(3.0%0));
System.out.print(" ");
System.out.println(
Double.isNaN(3.0/0));
}//end main()
}//end class definition
what is the output of above program and y ?
thanks
rahul
 
Kishore Pamu
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The output of the above code is :
true false.
because 3.0%0 gives NaN and 3.0/0 gives infinity.
 
sai challa
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Originally posted by Rahul Pawar:
class Q81{
public static void main(
String args[]){
System.out.print(
Double.isNaN(3.0%0));
System.out.print(" ");
System.out.println(
Double.isNaN(3.0/0));
}//end main()
}//end class definition
what is the output of above program and y ?
thanks
rahul

The output of the above program is true false.
Dividing a double by zero produces the result of Infinity.The value 'Infinity' indicates an effectively infinite result,in that it is greater than the largest number that can be represented as type double.
The operation 3.0%0 produces an indeterminate result.Hence the value of the output will be NaN.The value is referred to as Not-a-Number,indicating an indeterminate value.
 
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