Exception Problem

[Jyotsna Umesh]

Hi JavaRanchers,
Please explain why the answer to this problem is compilation error?
public class ThrowsDemo {
static void throwMethod() {
System.out.println("Inside throwMethod.");
throw new IllegalAccessException("demo");
}
public static void main(String args[]) {
try {
throwMethod();
} catch (IllegalAccessException e) {
System.out.println("Caught " + e);
}
}
}
[a] Compilation error
[b] Runtime error
[c] Compile successfully, nothing is printed.
[d] inside demoMethod. followed by caught: java.lang.IllegalAccessException: demo
Thanx
Jyotsna

[Scott Appleton]

Jyotsna,
If a method can or does throw a checked Exception, then it must either declare that it does via a "throws" clause in the method signature

static void throwMethod() [B]throws IllegalAccessException[/B] {

or else it must place the statement which may throw a checked exception within a try-catch block

try {
System.out.println("Inside throwMethod."); 
                       throw new IllegalAccessException("demo"); 
                       } catch (IllegalAccessException e) {;}

The code you posted does neither, so the compiler complains.

[Jyotsna Umesh]

Thanks Scott for the explanation, its silly of me, i didn't check this.
Jyotsna

Originally posted by Scott Appleton:
[B]Jyotsna,
If a method can or does throw a checked Exception, then it must either declare that it does via a "throws" clause in the method signature

static void throwMethod() [b]throws IllegalAccessException[/B] {

or else it must place the statement which may throw a checked exception within a try-catch block

try {
System.out.println("Inside throwMethod."); 
                       throw new IllegalAccessException("demo"); 
                       } catch (IllegalAccessException e) {;}

The code you posted does neither, so the compiler complains.[/B]