Final Variables -- No . 2

[padmini Babu]

What is the result of attempting to compile the following code and then execute the class Outward?
1. class Outward {
2. final int i = 10;//LINE 1
3.
4. public static void main(String[] args) {
5. new Outward ();
6. }
7.
8. Outward {
9. (new Inward()).foo();
10. }
11.
12. class Inward {
13. void foo() {
14. int i = 20;
15. System.out.println("i = " + i);
16. }
17. }
18. }
D) Line 15 prints out "i = 20".
Correct selection is: D
The code has two variables with the name "i". The one with the innermost scope (on line 14) shadows the one on line 2, so line 15 prints out "i = 20".
DOUBT: WHY DOES SHADOWING OCCUR HERE AND WHY DOES IT NOT OCCUR IF I REMOVE FINAL FROM LINE 1.
IT IS SAID THAT FINAL VALUES CANNOT BE ASSSINGED ONCE AGAIN BUT HERE IT IS REDECLARED.
Thanks in advance
Padmini

[Vanitha Sugumaran]

Hi,
In the method foo() int i is local variable. So changes made on this local variable doesn't affect the final variable.
Vanitha.