ServerSocket question

Hi all
i've set the ServerSocket constructor to accept 1 connection i.e ( ServerSocket socket = new ServerSocket(5000,1);
However if the server socket has already accepted a connection and another client socket tries to connect to it , it sucessfully makes a connection to the ServerScocket though the ServerSocket does not accept it (The client socket does not even throw an exception) . How can i prevent the client socket from making a connection to the serversocket if the serversocket has already accepted a connection ?
Thanks in advance

Any inputs ?

You're not setting the maximum # of connections accepted -- you're setting the length of the queue of clients waiting to be accepted. If the queue is full, the connection is rejected.
Not sure if a queue size 0 would actually work.
- Peter

Originally posted by Peter den Haan:
You're not setting the maximum # of connections accepted -- you're setting the length of the queue of clients waiting to be accepted. If the queue is full, the connection is rejected.
Not sure if a queue size 0 would actually work.
- Peter

I,am not using a while loop that means i,am allowing only one conection at one time . Secondly i've specified the que length as 1.

And your second client is patiently sitting in your 1-deep queue, waiting for its turn to be served.
- Peter

Thats the point . Why should my second client who connects to the server wait when the server is accepting just one connection and secondly it is not even accepting connections in a while loop.
Should not the second client who connects to this server throw a connection refused sort of Exception.

Originally posted by Peter den Haan:
And your second client is patiently sitting in your 1-deep queue, waiting for its turn to be served.
- Peter

Did you try a 0 queue depth? As I said, I'm not sure if it's legal or not, but worth a try.
- Peter