URL.openStream()

[Roger Shields]

I'm trying to read the contents of the reverse lookup page from 411.com at
http://www.411.com/10668/search/ReversePhone?phone=8001234567. (Replace 8001234567 with any number.

But anyway, I get a java.io.IOException with the message of
"Server returned HTTP response code: 403 for URL: http://www.411.com/10668/search/ReversePhone?phone=8001234567".

But if you enter the url into your browser it brings up a web page.

Now my question, I'm wondering if anyone has any idea of what I can do to actually get the content of the page?

[Jesus Angeles]

Have you tried HttpURLConnection?

[Roger Shields]

Yes, tried both. I can enter most other URLs, like http://www.google.com and it works fine. My best guess is that it is a problem with the user agent or something.

[Henry Wong]

An error code 403 is basically an "access denied" error code. It means that there is something with the request that the site doesn't like. Anyway, I took a quick look... and I guess there is a check to only work for supported browsers. So if you fake it out with something like this:

URL in = new URL("http://www.411.com:80/10668/search/ReversePhone?phone=8001234567");
 
URLConnection conn = in.openConnection();
 
conn.addRequestProperty("user-agent", "Mozilla/4.0");
InputStream in = conn.getInputStream();

It seems to work.

Henry
[ January 20, 2007: Message edited by: Henry Wong ]