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question about rmi registry

 
zb cong
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Posts: 416
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hello
i write a simple interface "Hello.java",i want to call it by rmi,after "javac","rmic","rmiregistry",i want to start "RMIServer.class" that is used to register in the server,see my code:
==================================================public
class RMIServer{
private static final int PORT=1099;
private static final String HOSTNAME="127.0.0.1";
public RMIServer()
throws RemoteException,
MalformedURLException,
NotBoundException{
LocateRegistry.createRegistry(PORT);
System.out.println("registry:"+HOSTNAME+" in "+(Integer.toString(PORT)));
Hello h=new HelloImpl();
System.out.println("remote object has be created");
String urlString="//"+HOSTNAME+":"+Integer.toString(PORT)+"/HelloService";
Naming.rebind(urlString,h);
System.out.println("binding finished");
}
public
static
void
main(String argv[]){
System.setSecurityManager(new RMISecurityManager());
try{
RMIServer rs=new RMIServer();
}catch(Exception e){
System.err.println(e);
}
}
=================================================
i type"java RMIServer",it tell me:
==================================================java.rmi.server.ExportException: Port already in use: 1099; nested exception is:
java.net.BindException: Address already in use: JVM_Bind
==================================================
then i modify the port number to "10002",it said:
==================================================
registry:127.0.0.1 in 10002
remote object has be created
java.security.AccessControlException: access denied (java.net.SocketPermission
127.0.0.1:10002 connect,resolve)
==================================================
who can tell me why?
thanks alot
 
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