# The Conditional Operator ?:

md ali

Greenhorn

Posts: 25

posted 14 years ago

- 0

Hi All,

I am unable to read this statement written using ? operator.

a = b ? c ? d : e ? f : g : h ? i : j ? k : l ;

If any one can tell me whihc is true part of which and which is false part. To me this statement seems look like this.

if b is true then we go the true part and that is that we check c that if c is true. And if it is true then we finish at d by reutring the value of d.

But what if b is false what will be returned.

And now if we find b true, then c false and e false then we eand up at g. Can someone explain me what wil the case theat we will reach at k or l. Or if some one can write an algorithmic form of this expression.

Regards

Muhammad Ali

I am unable to read this statement written using ? operator.

a = b ? c ? d : e ? f : g : h ? i : j ? k : l ;

If any one can tell me whihc is true part of which and which is false part. To me this statement seems look like this.

if b is true then we go the true part and that is that we check c that if c is true. And if it is true then we finish at d by reutring the value of d.

But what if b is false what will be returned.

And now if we find b true, then c false and e false then we eand up at g. Can someone explain me what wil the case theat we will reach at k or l. Or if some one can write an algorithmic form of this expression.

Regards

Muhammad Ali

Valentin Crettaz

Gold Digger

Sheriff

Sheriff

Posts: 7610

posted 14 years ago

- 0

Hi,

the statement is to be read like follows,

a = (b ? (c ? d : (e ? f : g)) : (h ? i : (j ? k : l)));

See JLS 15.24

Val

the statement is to be read like follows,

a = (b ? (c ? d : (e ? f : g)) : (h ? i : (j ? k : l)));

See JLS 15.24

Val

SCJP 5, SCJD, SCBCD, SCWCD, SCDJWS, IBM XML

[Blog] [Blogroll] [My Reviews] My Linked In

Valentin Crettaz

Gold Digger

Sheriff

Sheriff

Posts: 7610

posted 14 years ago

- 0

Sorry, i submitted too quickly...

a = (b ? (c ? d : (e ? f : g)) : (h ? i : (j ? k : l)));

1. if b is true then we evaluate (c ? d : (e ? f : g)) (the first part) else the second part (h ? i : (j ? k : l))

2. the same for each part:

if b is true and c is true then a=d

if b is true and c is false and e is true then a=f

if b is true and c is false and e is false then a=g

if b is false and h is true then a=i

if b is false and h is false and j is true then a=k

if b is false and h is false and j is false then a=l

Hope it helps,

Val

a = (b ? (c ? d : (e ? f : g)) : (h ? i : (j ? k : l)));

1. if b is true then we evaluate (c ? d : (e ? f : g)) (the first part) else the second part (h ? i : (j ? k : l))

2. the same for each part:

if b is true and c is true then a=d

if b is true and c is false and e is true then a=f

if b is true and c is false and e is false then a=g

if b is false and h is true then a=i

if b is false and h is false and j is true then a=k

if b is false and h is false and j is false then a=l

Hope it helps,

Val

SCJP 5, SCJD, SCBCD, SCWCD, SCDJWS, IBM XML

[Blog] [Blogroll] [My Reviews] My Linked In

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