equals!

[ashok khetan]

hi! can u pl explain the output of this code? i think in stat 1 internally the toString() method is called so there shouldn't be any difference between 1 & 2.
thanx.
ashok.
____________
class MyClass {
public static void main(String args[ ]) {
Integer i = new Integer(10);
System.out.println(i == i); //1--> true
System.out.println(i.toString() == i.toString());//2--> false
}
}
____________

[Roopa Bagur]

My understanding is toString method returns a new string object.Since == checks the reference of the objects .== would fail comparing to different string objects.
Anybody correct me if I am wrong.

Originally posted by ashok khetan:
hi! can u pl explain the output of this code? i think in stat 1 internally the toString() method is called so there shouldn't be any difference between 1 & 2.
thanx.
ashok.
____________
class MyClass {
public static void main(String args[ ]) {
Integer i = new Integer(10);
System.out.println(i == i); //1--> true
System.out.println(i.toString() == i.toString());//2--> false
}
}
____________

[Ragu Sivaraman]

Yeap, toString() returns a new object
so == shallow wont cut it
check the hashcode to verify it

[marilyn murphy]

Originally posted by ashok khetan:

<font size=+0>
class MyClass 
{
    public static void main(String args[ ]) 
    {
        Integer i = new Integer(10);
        System.out.println(i == i);  //1--> true
        System.out.println(i.toString() == i.toString());//2--> false
    }
}

i == i is done first (i.e. 10 == 10 ) = true.
Then the result (i.e. "true") is changed to a String by the implicit toString().
You know that if you use ( i.toString() ).equals( i.toString() ) you will get "true" for the result.