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Encoding style not supported

Amol Desai
Ranch Hand

Joined: Jan 29, 2003
Posts: 82
I am using DII(jaxrpc1.0) to invoke a web service running at http://otn.oracle.com/ws/oracle.otn.ws.scott.OTNDeptEmp
wsdl file is available there.
Following are the exceptions I get.
encoding style: "http://xml.apache.org/xml-soap/literalxml" not supported
at com.sun.xml.rpc.client.dii.BasicCall.getRequestSerializer(BasicCall.java:379)
at com.sun.xml.rpc.client.dii.BasicCall.invoke(BasicCall.java:279)
at otndeptclient.main(otndeptclient.java:87)
Code to invoke web service is as below:

import javax.xml.rpc.Call;
import javax.xml.rpc.Service;
import javax.xml.rpc.JAXRPCException;
import javax.xml.namespace.QName;
import javax.xml.rpc.ServiceFactory;
import javax.xml.rpc.ParameterMode;
public class otndeptclient {
private static String qnameService = "OTNDeptEmp";
private static String qnamePort = "OTNDeptEmpPort";
private static String BODY_NAMESPACE_VALUE =
private static String ENCODING_STYLE_PROPERTY =
private static String NS_XSD =
private static String URI_ENCODING =
public static void main(String[] args) {
try {
String endpoint= "http://otn.oracle.com/ws/oracle.otn.ws.scott.OTNDeptEmp";
ServiceFactory factory = ServiceFactory.newInstance();
Service service =factory.createService(new QName(qnameService));
QName port = new QName(qnamePort);
Call call = service.createCall(port);
new Boolean(true));
call.setProperty(Call.SOAPACTION_URI_PROPERTY, "");
QName QNAME_TYPE_STRING = new QName(NS_XSD, "string");
call.setOperationName(new QName(BODY_NAMESPACE_VALUE,
String[] params = { };
String result = (String)call.invoke(params);
} catch (Exception ex) {
How do I overcome this problem, please let me know.
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subject: Encoding style not supported
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