Reg. Assigning values

[Angela Narain]

When we assign a value to say a byte variable as below :
byte b = 3;
Here we see that the right side literal value should
be in the range of the byte i.e. ( -128 to 127 ) , so the
assignment is valid and code compiles and runs fine.
My doubt :
1. For the character variable assigining a int value should be in the
range of (0-65535).
Does it work the same way as mentioned above?
2. Is it that beyond the range of the variable to which we are assigning
it is considered as an int.?
( I am referring specifically to assigning to byte,short,char variables )

[Fisher Daniel]

Hi,
you can create char = 655; it is compile and run time success
thanks
daniel

[Anonymous]

Originally posted by Angela Narain:

When we assign a value to say a byte variable as below :
byte b = 3;
Here we see that the right side literal value should
be in the range of the byte i.e. ( -128 to 127 ) , so the
assignment is valid and code compiles and runs fine.
My doubt :
1. For the character variable assigining a int value should be in the
range of (0-65535).
Does it work the same way as mentioned above?
2. Is it that beyond the range of the variable to which we are assigning
it is considered as an int.?
( I am referring specifically to assigning to byte,short,char variables )

Hi Angela,
Small example here.

<font size="+0">
 public class Example1{
  public static void main( String args[]){
    
    char c0 = 0;
    char c6 = 126;
    char c7 = 127;
    char c8 = 128;
    char sth = 655; // sth = something.
    char cn = (char)-1; // cn = c negative. Compiler asks for explicit cast
    
    System.out.println("Value of C0 = " + c0);
    System.out.println("Value of C6 = " + c6);
    System.out.println("Value of C7 = " + c7);
    System.out.println(" Any thing after this will print only \'?\' for the value of the variable");
    System.out.println("Value of C8 = " + c8);
    System.out.println("Value of Csth = " + sth);
    System.out.println("Value of Cn = " + cn);  
    
/*
  This is because, " The first 128 characters of the Unicode set
are the same as the 128 characters of the 7-bit ASCII 
character set."  It will not recognize values which are not in this range.
*/
  }
}
</font>

HIH,
Guru's correct me!
chandrashekar

[Jane Griscti]

Hi all,
Integral literals are treated as ints. When they appear in an assignment, for example, in <code>byte b = 3</code> the '3' is an int but Java applies assignment conversion and because '3' is within the range of a byte, the assignment succeeds.
The same is true for <code>char c = 655</code>.
See JLS §5.2
------------------
Jane Griscti
Sun Certified Programmer for the Java� 2 Platform

[Anonymous]

It will not recognize values which are not in this range.

Hi Jane Griscti,
As we can see from the example above, I am sure that the code will compile and run when we use
char c = 655. [Narrowing conversion involving int literals] But when we are trying to print out the value, why is it not printing any value. It is printing a '?' . what does that mean. Can you please clarify on that.
thanks
Chandrashekar!

[Anonymous]

Hi all,
I got the info after reading it from Khalid's book. (pg
"Not all Unicode Characters can be represented in other encoding schemes. In that case, the ? character is usually used to denote any such character in the resulting output, during translation from Unicode.
thanks
Chandra!
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Where there is a Will, there is a Way.