Hi As per Java Specification for round method of Math If the argument is negative infinity or any value less than or equal to the value of Integer.MIN_VALUE, the result is equal to the value of Integer.MIN_VALUE. If the argument is positive infinity or any value greater than or equal to the value of Integer.MAX_VALUE, the result is equal to the value of Integer.MAX_VALUE. So I tried these 2 below lines. System.out.println(Math.round(Integer.MIN_VALUE-1)); System.out.println(Math.round(Integer.MAX_VALUE+1)); And the result is giving 2147483647 -2147483648 So it seems to me that If the argument is less than the value of Integer.MIN_VALUE, the result is equal to the value of Integer.MAX_VALUE. If the argument is greater than the value of Integer.MAX_VALUE, the result is equal to the value of Integer.MIN_VALUE. Could anybody explain the above.

the reason is the following the maximum integer value is 0x7FFFFFFF when you add 1 (0x00000001) you get 0x80000000 which is Integer.MIN_VALUE. the same goes for the opposite. The thing to remember is that there is no overflow with integer. HIH ------------------ Valentin Crettaz Sun Certified Programmer for Java 2 Platform

The parameters you passed in are not really less than Integer.MIN_VALUE or greater than MAX_VALUE. They are just result of integer operation being promoted to float. As Val mentioned, integer operations are wrapped around. So, you should do something like followings to verify the API.

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