flow of execution

hi
1) how is the flow of execution of a program.
static variable-->static intializer-->instance variable-->instance initializer-->constructor of superclass-->constructor of subclass
Am i right.
2) when a no arg constructor of subclass is called then which constructor of superclass is called.
Is it only the no arg constructor or also the matching constructor in superclass is called or no constructor from super class is called.

1) how is the flow of execution of a program.
static variable-->static intializer-->instance variable-->instance initializer-->constructor of superclass-->constructor of subclass
Am i right.

a note, Depends on whichever come first too.

2) when a no arg constructor of subclass is called then which constructor of superclass is called.
Is it only the no arg constructor or also the matching constructor in superclass is called or no constructor from super class is called.[/B]
if u didn't put super(....) it is the no arg constructor
of super class. If no super(...) and this(...) complier will put super() for you.

"instance variable-->instance initializer-->constructor of superclass"
it's the other way round, remember the superclass instances should be initialized before subclasses instances.
hope helps

class Superclass
{
Superclass()
{System.out.println("1");
}
Superclass(int a)
{S.o.p("2");
}
}
class Subclass extends Superclass{
Subclass()
{S.o.p("3");
}
Subclass(int b)
{S.o.p("4");
}
public static void main(String args[])
{
Subclass s= new Subclass(5);}
}
what will the output be?
Will it be 4

In my oppinion, the output will be 1 and 4. The constructor in the subclass will call the "no-parameter" constructor from the superclass and then it will take care of himself.
Correct me if I'm wrong.

Got it
but just to confirm once again the constructor of the subclass will not call its no arg costructor but only the no args constructor of super class and if the superclass has no args constructor then will print only 4.
correct me if i am wrong
thanx in advance
neha