Reg. Thread basics question

[Angela Narain]

class MyThread1 extends Thread {
  public void run()
  {
        System.out.println(" Inside run " + Thread.currentThread());
synchronized(this){
             System.out.println(" Value of this " + this );
     System.out.println(" Inside synchronized \n\n");
        }
  } 
  public static void main( String[] args )
  {
     //MyThread1 t = new MyThread1();
     new MyThread1().start(); //1
     new MyThread1().start(); //2
  }
}

Can someone explain me the lines //1 and //2 and the effect
of creating this threads and calling the run method.
How will they be synchronized ?

[Mr. C Lamont Gilbert]

Can someone explain me the lines //1 and //2 and the effect
of creating this threads and calling the run method.
How will they be synchronized ?

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</BLOCKQUOTE>

Since they are each synchronized with respect to themselves, there will be no visible effect of the synchronization. They are seperete objects synchronized on seperate things.

[This message has been edited by CL Gilbert (edited October 08, 2001).]
[This message has been edited by CL Gilbert (edited October 08, 2001).]