shift...Can any one explain me>?

I still cannot understand how are we supposed to calculate such nos.
I went through a mock and found a question :
128 >> 1 gives 64
128 >>> 1 gives 64
128 << 1 gives 256

Ans : All are true.Can any one explain me how is the above expressions true?..with EXPLAINATIONS!!
Sonir

This has been discussed many times. Do a search in this forum for "shift".

Let me C if I cud B of help.....
these R really crude methods....
RightShift
x >> n
simply means divide x by (2^n)
thus
eg no 1.
128 >> 3
means 128 / (2^3)
=128 / 8
=16
eg no. 2
127 >> 3
=127 /8
=15 (forget the decimal business...)
Catch here is of -ve numbers :::
-127 >> 3
= -(15+1)
= -16
Similarly,
LeftShift means multiply by 2^n
thus 12 << 3<br /> =12*8<br /> =96<br /> Now comes the unsigned right shift >>>
For positive numbers its the same as >>
so 128 >>> 3
=128/8
=16
for -ve numbers the fundas R required....
no crude methods can help U with these ...

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