Promotions?

[sonir shah]

public class PromotionTest
{
   public static void main(String args[])
   {
      int i = 5;
      float f = 5.5f;
      double d = 3.8;
      char c = 'a';
      if (i == f) c++;
      if (((int) (f + d)) == ((int) f + (int) d)) c += 2;
      System.out.println(c);
   }
}

Options are :
1)Code will fail to compile
2)It will print d
3)It will print c
4)It will print b
5)It will print a
Ans : 5)It will print a
I tried running the program , it prints "a"
I feel that the statement(i=f) is not correct and even c++ is wrong?
Am i right?
A bit confused since I cannot understand how are we getting such an output??
Any suggestions?

[Valentin Crettaz]

the answer is correct. a char primitive contains a numeric value, thus comparison and incrementation are valid operations for chars.

[Tony reedy]

The expressions are correct.
When "if (i == f) c++;" is evaluated ,i is converted to float and so 5.0 . As 5.0 != 5.5 ,C++ is not evaluated
when"if (((int) (f + d)) == ((int) f + (int) d)) c += 2;"
f+d is added to get a double value 9.3 which is casted to int and result is 9 .
(int)f =5 + (int)d= 3 and the result will be 8.
9!= 8 so rest of the expression is not evaluated
so the answer is 'a'.
hope this explains.

[Rob Ross]

This is a good discussion of assignment of literals that's also useful to understand:
http://www.javaranch.com/cgi-bin/ubb/ultimatebb.cgi?ubb=get_topic&f=24&t=014061