Is the expression correct??

[sonir shah]

public class TestClass
{
   public static void main (String args[ ] ) 
   {
      int k = 1;
      int i = ++k + k++ + + k ;
      System.out.print(i+ " "+ k) ;
   }
}

Options : 1)Compilation error at: "++k+k++ + + k" expression]
2)Compile and will print 7 and 3
3)Compile and will print 5 and 2
4)Compile and will print 9 and 3
5)Compile and will print 5 and 3
The answer is :2) It will compile and will print the value 7 and 3 when run.
I feel the asnwer is 3).
because value assigned to i will be 5 in the end and the value assigned to k will 2(twice ++k)
please explain.
Sonir

[Mike Beaty]

You have:

int k = 1;   
int i = ++k + k++ + + k ;  

after ++k, k is 2
then 2 + 2
then add one to k
then you have 2 + 2 + 3, for i

[Arsho, Ayan]

Hi Sonir ...
I hope this helps
visualize the expression as
++k + k++ + +k
(2)1 + 2(3) + +3 = 7 i.e i
Now add only the right side of each element.
ie 2+2+3
the value of k will be 3
Later
[ January 12, 2002: Message edited by: Arsho, Ayan ]

[Madhav Lakkapragada]

Some of the best ++ operations that we discussed in the past....atleast I could understand.
1. http://www.javaranch.com/ubb/Forum24/HTML/000775.html
2. http://www.javaranch.com/cgi-bin/ubb/ultimatebb.cgi?ubb=get_topic&f=24&t=001715
regds.
- satya

[Madhav Lakkapragada]

(2)1 + 2(3) + +3 = 7 i.e i
Now add only the right side of each element.
ie 2+2+3

That would be :
(2)2+ 2(3) + +3 = 7 i.e i
Now add only the right side of each element.
ie 2+2+3
If I am NOT mistakes.
- satya

[Ragu Sivaraman]

Originally posted by sonir shah:

public class TestClass
{
   public static void main (String args[ ] ) 
   {
      int k = 1;
      int i = ++k + k++ + + k ;
      System.out.print(i+ " "+ k) ;
   }
}

Options : 1)Compilation error at: "++k+k++ + + k" expression]
2)Compile and will print 7 and 3
3)Compile and will print 5 and 2
4)Compile and will print 9 and 3
5)Compile and will print 5 and 3
The answer is :2) It will compile and will print the value 7 and 3 when run.
I feel the asnwer is 3).
because value assigned to i will be 5 in the end and the value assigned to k will 2(twice ++k)
please explain.
Sonir

Be careful with this post/pre incrementors
people love asking questions on this . donno why
int i = ++k + k++ + + k ;
++k, increments itself and then gives it to i
so its equal to 2
k++ , gives its value 2 to the 'i' to participate in the addition ( ++k + k++) and then increments itself..
+ +k - this incremented k is again added , so the value of i is 7 and k is 3
hope you got it
Ragu