I have found the best way to attack any loop question like this is by writing up a small chart on paper & incrementing your variables like that. Keeping track of this by eye can be flustering. In this example the values going thru the loops are as follows: i-k repectively. Remeber when the condition is true the prog breaks(first line after the if since no braces are used, when false it increments counter. 000 (0-0>0)false counter 1 001 (1-0>0) true counter=1 011 (1-1>0) false counter=2 012 (2-1>0) true counter=2 022 (2-2>0) false counter=3 After that you start dropping out of the loops because you have incremented k, j to 3 (respectively) The outer loop then increments but the inner variables are already 3 so nothing happens in those loops. [ January 13, 2002: Message edited by: DC Dalton ]
I think the value of i in outer instead j in middle is incremented after every "break middle" statement. pls see the following code
the result will be i=0 j=0 k=0 counter=1 i=0 j=0 k=1 i=1 j=0 k=0 counter=2 i=1 j=0 k=1 i=2 j=0 k=0 counter=3 i=2 j=0 k=1 3 [ January 13, 2002: Message edited by: patrick tang ]
Joined: Nov 01, 2001
Hey guys I am still not clear with the concept.I tried working it out on a paper. i=0,j=0,k=0 (0-0>0) false i=0,j=0,k=1(1-0>0)true--->counter 1; i=0,j=1,k=1(1-1>0)false i=0,j=1,k=2(2-1>0)true---->counter 2; 1=0;j=2,k=2(2-2>0)false I am thorough till here.Can any one explain me the steps from now with reasons..
Joined: May 28, 2001
Well when your wrong your wrong, (serves me right for trying to answer a question while studying!) The label is used with the break to terminate THAT loop and any inside of it. So as I was so correctly corrected i increments NOT the inner variables. Put printlns after each for statement and after the counter increment & you will see the results step by step. This is what comes out: F:\JavaProgs>java LoopTest i is: 0 j is: 0 k is: 0 Counter is: 1 k is: 1 i is: 1 j is: 0 k is: 0 Counter is: 2 k is: 1 i is: 2 j is: 0 k is: 0 Counter is: 3 k is: 1 3 So the final answer is 3. [ January 13, 2002: Message edited by: DC Dalton ]
I’ve looked at a lot of different solutions, and in my humble opinion Aspose is the way to go. Here’s the link: http://aspose.com