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'if'block ??

sonir shah
Ranch Hand

Joined: Nov 01, 2001
Posts: 435
What will the following program print?

I tried running the program, it printed "false false"
I cannot understand the if/else block i.e
if( b )
x = ( ch == ia[ch]);
else x = ( ba[ch] = b );
Can any one explain me??
DC Dalton
Ranch Hand

Joined: May 28, 2001
Posts: 287
The boolean b is automatically intialized to false. The char ch is automatically initialized to \u0000 which is 0 (Remember you can use Unicode anywhere in your code) so the if statement reads like this if (false) // skips the if section and goes to the else block. The assignment else x = ( ba[ch] = b ); will break down like this
else x = ( ba[ch] = b ); //original
else x = (ba[0] = false); // first op
else x = (false); 2nd op
So the sys print will print
System.out.println(false" "+false);
patrick tang
Ranch Hand

Joined: Dec 16, 2001
Posts: 44
member variables will be given default value if they're not initiated. so
so in if block, as b is false, it'll go to else statement. b(false) is first assigned to ba, then x. so both x and ba[ch] are false
I agree. Here's the link:
subject: 'if'block ??
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