'if'block ??

[sonir shah]

What will the following program print?

public class TestClass 
{
static boolean b;
static int[] ia = new int[1];
static char ch;
static boolean[] ba = new boolean[1];
public static void main(String args[]) throws Exception
{
boolean x = false;
if( b )
{ 
x = ( ch == ia[ch]);
}
else x = ( ba[ch] = b );
System.out.println(x+" "+ba[ch]);
}
}

I tried running the program, it printed "false false"
I cannot understand the if/else block i.e
if( b )
{
x = ( ch == ia[ch]);
}
else x = ( ba[ch] = b );
Can any one explain me??
Sonir

[DC Dalton]

The boolean b is automatically intialized to false. The char ch is automatically initialized to \u0000 which is 0 (Remember you can use Unicode anywhere in your code) so the if statement reads like this if (false) // skips the if section and goes to the else block. The assignment else x = ( ba[ch] = b ); will break down like this
else x = ( ba[ch] = b ); //original
else x = (ba[0] = false); // first op
else x = (false); 2nd op
So the sys print will print
System.out.println(false" "+false);

[patrick tang]

member variables will be given default value if they're not initiated. so
b=false
ia=0
ch='\u0000'
ba=false
so in if block, as b is false, it'll go to else statement. b(false) is first assigned to ba, then x. so both x and ba[ch] are false