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Can't understand such an output..

sonir shah
Ranch Hand

Joined: Nov 01, 2001
Posts: 435

Options :
1)It generates a compile error at line 4
2)It generates a compile error at line 5
3)If the cast on line 5 were miited, then line 5 would not compile
4)The code compiles and prints "b=0"
5)The code compiles and prints"b= -2"
6)The code compiles and prints "b= -3"
7)The code compiles and prints "TROUBLE"
Ans :3) and 6)
I cannot understand from where did this "-3" come?
Please explain?
Sonir
Rob Ross
Bartender

Joined: Jan 07, 2002
Posts: 2205
All numbers in java are signed, ie, they can be + or -.
The lines
short s = 0x00FD;
byte b = (byte)s;
cause the value 0xFD to be stored in the variable b.
0xFD is hexidecimal for -3 using signed numbers.
just remember that OxFF is -1, and count backwards from there...
FF = -1
FE = -2
FD = -3
FC = -4...
...
80 = -128
...
7F = 127
7E = 126...
etc.
Rob


Rob
SCJP 1.4
 
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subject: Can't understand such an output..