I assume that you know what the >> operator do. In fact if the right hand side operator is 32, it just do nothing. The explanation come from the modulo. 32 modulo 32 =0 so do nothing. 32 modulo 31 =31 so do 31 32 modulo 33 =1 so do 1. So if you do int >> 33 or int >>1 it just do the same thing. I hope my explanation is helpfull!!! If not,do not hesitate to contact me. Sorry for my english

Younes
By constantly trying one ends up succeeding. Thus: the more one fails the more one has a chance to succeed.

Younes Essouabni
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Joined: Jan 13, 2002
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It's just the wrong it's 32 modulo 32=0 33 modulo 32=1 31 modulo 32=31

System.out.println(32>>32);//case1 the result show : 32 System.out.println(32>>31);//case2 the result show : 0

For shift operators, 'only the five lowest-order bits of the right-hand operand are used as the shift distance, if the left-hand operand is int'. In case1, the 5 bits are: 00000. So, the left-hand operand (32) gets shifted by 0 bits and hence the result is the same: 32. In case2, the 5 bits are: 11111. So, the left-hand operand (32) gets shifted by 31 bits and hence the result is: 0.

I see that your are new to this forum. Plz do a search for your question before you post. This has been discussed many times before.

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