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Flow Control.......

sonir shah
Ranch Hand

Joined: Nov 01, 2001
Posts: 435

Options :
1)2
2)3
3)6
4)7
5)9
I tried running the code and got the output as 3.
Can any one make me understand the flow of the code?
Sonir
Arsho, Ayan
Ranch Hand

Joined: Nov 14, 2001
Posts: 60
Hi Sonir :
write it this way
i=0;j=0;k=0 counter will be 0(1)
i=0;j=0;k=1 break's out
i=1;j=0;k=0 counter will be 1(2)
i=1;j=0;k=1 break's out
i=1;j=0;k=0 counter will be 2(3)
i=1;j=0;k=1 break's out
i=2;j=0;k=0 counter will be 3(4)
i=2;j=0;k=1 break's out
So the answer 3 will be printed.
Hope this helps
-A
mark stone
Ranch Hand

Joined: Dec 18, 2001
Posts: 417
first ......i=0 j=0 k=0, counter =1
second ........... k=1, break middle and enter outer
third ...... i=1 j=0 k=0 counter =2
fourth ........... k=1 break middle and enter outer
fifth i=2 j=0 k=0 counter =3
......... k=1 break middle and enter outer
and it stops as i cannot be incremented further.
hope this helps....


Options :
1)2
2)3
3)6
4)7
5)9
I tried running the code and got the output as 3.
Can any one make me understand the flow of the code?
Sonir[/qb]<hr></blockquote>
[ January 23, 2002: Message edited by: mark stone ]
 
I agree. Here's the link: http://zeroturnaround.com/jrebel - it saves me about five hours per week
 
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