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Hexadecimal calculation

 
simon kumar
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Hi,
can anyone tell me what is the simplest way to calculate 0x67^0xBD,the result is 0xDA
simon
 
Dave Vick
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Simon
The ^ operator is the 'exclusive or' that operates on the individual bits of the operands. In the example you gave
0x67^0xBD
The way to do it is to convert the hex into binary. I have to go through decimal to do it
0x67 is 103 in decimal and 0xBD is 189, in binary they are (remember that ints are 4 bytes):
00000000 00000000 00000000 01100111
00000000 00000000 00000000 10111101
the results of your 'exclusive or' are:
00000000 00000000 00000000 11011010
which equates to: 218 in decimal or 0xDA in hex.
Remember the ^ means that the result is one if one, but not the other, of the bits is a 1.
hope that helps
 
Donald Yee
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Easiest way is to convert to binary.
0x67 = 0110 0111
^ 0xBD = 1011 1101
------------------
1101 1010 = 0xDA
 
Corey McGlone
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Originally posted by simon kumar:
Hi,
can anyone tell me what is the simplest way to calculate 0x67^0xBD,the result is 0xDA
simon

Convert to binary!
Every hexadecimal number is equivalent to 4 bits. Therefore, you can convert from hex to binary very easily.
0x67 = 01100111
0xBD = 10111101
Now, just XOR the bits:
0x67^0xBD = 11011010
Then, convert back to hex:
1101 = D
1010 = A
Therefore, your final answer is 0xDA.
Happy hexing!
Corey
 
Valentin Crettaz
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here is a link that might be worth reading:
Javaranch campfire:Cat and Mouse Games with Bits
[ February 22, 2002: Message edited by: Valentin Crettaz ]
 
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