Exceptions

[vinita Kh]

nebody plz explain the output of this code, why compile time error?

public class ThrowsDemo {  
      static void throwMethod() {  
              System.out.println("Inside throwMethod.");  
               throw new IllegalAccessException("demo");  
      }  
      public static void main(String args[]) {  
           try {  
                 throwMethod();  
           } catch (IllegalAccessException e) {  
                 System.out.println("Caught " + e);  
           }  
       }  
}

[ Added UBB [ CODE ] tags to add whitespace and improve readability ]
[ May 12, 2002: Message edited by: Jessica Sant ]

[Chintan Rajyaguru]

The following part of the code has trouble
static void throwMethod() {
System.out.println("Inside throwMethod.");
throw new IllegalAccessException("demo");
}
throwMethod actually throws exception. So, either the IllegalAccessException exception (or its superclass) should be cought or the method has to declare that it throws IllegalAccessException exception (or its super class).
try changing the method as
static void throwMethod()
throws IllegalAccessException
{
System.out.println("Inside throwMethod.");
throw new IllegalAccessException("demo");
}