Strings

[Arun Pai]

What are legal operations on s?
String s = "something";
A.s >>= "ok";
B.char c = s[4];
C.s += 3;
D.s -= "thing";
E.s = s + "good";

Answer is C & E ??
-Arun

[Jose Botella]

Because it's possible to concatenate strings with the + operator. But it isn't possible to substract, shift or access them as they would be a char array.

[Jessica Sant]

Originally posted by Jose Botella:
Because it's possible to concatenate strings with the + operator. But it isn't possible to substract, shift or access them as they would be a char array.

Exactly -- in Java the + operator is overloaded -- meaning it has a different function depending on the type of operands it is used with.
So C would produce the string "Something3"
and E would produce the string "Somethinggood"