Method overloading

[geetha nagarajan]

 class Try
 {
  public static void main(String s[])
  {
   Try t = new Try();
    t.test(15,20);//1
    t.test(20,20076);//2
  }
 static void test(short s,int i)
{
System.out.println("short,int");
}
 
static void test(int a,long l)
{
System.out.println("int,long");
}
}
  

Both //1 & //2 call test(int ,long) ,why not test(short,int).The values are within the range of short and int,right.
Pl.help.

[Corey McGlone]

Originally posted by geetha nagarajan:
The values are within the range of short and int,right.
Pl.help.

That's true, the values are within the range of a short, but literal integers in your application are automatically considered ints. Check out the JLS, §3.10.1 Integer Literals.
Corey