pls clarify

[bani kaali]

Can someone kindly tell me why the result is the AA's result is
20,10,30,31 and not 20,31,30,31 ?
class B{
protected int x;
B(){ x = 10;}
B(int a){ x = a;}
void m1(){x = 20;}
void m1(int x){this.x = x;}
}
public class AA {
int x;
AA(){x = 20;}
AA(int x){this.x = x;}
void m1(B x){this.x = x.x++;}
public static void main(String arf[]){
AA x = new AA(20);
B y = new B();
System.out.println(x.x);
x.m1(y);
System.out.println(x.x);
y.m1(30);
System.out.println(y.x);
((AA)x).m1(y);
System.out.println(y.x);
}
}
Thanks in advance
bani

[R K Singh]

Originally posted by bani kaali:
Can someone kindly tell me why the result is the AA's result is
20,10,30,31 and not 20,31,30,31 ?

class B{ 
     protected int x; 
     B(){ x = 10;} 
     B(int a){ x = a;} 
     void m1(){x = 20;} 
     void m1(int x){this.x = x;} 
    } 
    public class AA { 
     int x; 
     AA(){x = 20;} 
     AA(int x){this.x = x;} 
     void m1(B x){this.x = x.x++;} 
     public static void main(String arf[]){ 
      AA x = new AA(20); 
      B y = new B(); 
      System.out.println(x.x); // it will print 20
      x.m1(y); // AA.m1(B x) method is being called, which will set AA's x to 10 as B's default conctructor sets B's x to 10.
      System.out.println(x.x); // it will print 10
      y.m1(30); // B's x is set to 30
      System.out.println(y.x); // prints 30
      ((AA)x).m1(y); // you know it  :wink: 
      System.out.println(y.x); // you know it 
     } 
    } 

Thanks in advance
bani

[Jose Botella]

Hello Bani
I have stepped through the code jotting donw the values:
AA x = new AA(20); // x.x = 20
B y = new B(); // y.x = 10

x.m1(y); // x.x = 10
y.m1(30); // y.x = 30

((AA)x).m1(y); // x.x = 30 but later 31 because of x.x++ in m1
hope it helps