This week's book giveaway is in the OCAJP forum. We're giving away four copies of OCA Java SE 8 Programmer I Study Guide 1Z0-808 and have Jeanne Boyarsky & Scott Selikoff on-line! See this thread for details.
The following code will print 1: int i = 1; 2: i <<= 31; 3: i >>= 31; 4: i >>= 1; 5: 6: int j = 1; 7: j >>= 31; 8: j >>= 31; 9: 10: System.out.println("i = " +i ); 11: System.out.println("j = " +j); Ans is i = -1 and j =0; could any one tell me how i is -1 ?
each output line shows the binary representation of i. Note, the first line shows 1 as its binary representation because the leading zeros are omitted. Hope this helped. But basically it has to do with the fact that int has 32-bit size, and the left most bit is the sign bit that also happens to be the padding bit for >>. Remember >>> uses zero as its padding bit regardless of the sign bit.
Let us be showered in the light of confusion!
Joined: May 05, 2002
I didnt know about toBinaryString() .Thanks chung for helping me .