for loop!

[Akash Kumar]

When I run the following code, it runs fine.The answers say what is wrong with the above code? Can I anybody help me to select the correct answer.

for(int i=0;i<=22 ; )  {  
  if(i<= 10) { 
     int j= 2 + i; 
     i++; 
     // /* let us know */ // 
     System.out.println("i: " + i + " j: " + j); 
  } 
}

What is the error in the above code?
Ans. a. The loop will never terminate.
b. You cannot print integer values without converting them to strings.
c. The comment line is not formatted correctly.
d. You cannot declare variables inside a for-loop.
e. Variable j is referenced outside its scope.
Edited by Corey McGlone: Added Code Tags
[ July 18, 2002: Message edited by: Corey McGlone ]

[Corey McGlone]

Akash,
Welcome to Javaranch
We'd like you to read the Javaranch Naming Policy and change your publicly displayed name to comply with our unique rule. Thank you.
It looks to me like you've got an infinite loop there, so I'd say that 'a' is the correct answer.

[Malik Tahir]

Hi Akash,
Ans. A is right, b/c this loop will never terminate due to absence of increment.
Look closely u will find the error.
Bye

[swarna kumar]

malik is right,
for statement systax is wrong;
for(initialization;condition;iteration){
}
this is the syntax,here thers is no iteration part.
regds
swarna

[Corey McGlone]

Originally posted by swarna kumar:
malik is right,
for statement systax is wrong;
for(initialization;condition;iteration){
}
this is the syntax,here thers is no iteration part.
regds
swarna

All parts of a for loop are optional. You can leave out the initialization, conidition, and iteration statements. In the case that you leave out the condition statement, a true value is implied. The following is an infinite loop:

for ( ; ; )

Had the syntax been violated, a compiler error would have occurred - not an infinite loop.
Corey

[Akash Kumar]

Hi Folks
This runs fine. No systax error, no infinite loop also. Pls see below the output pls:
i: 1 j: 2
i: 2 j: 3
i: 3 j: 4
i: 4 j: 5
i: 5 j: 6
i: 6 j: 7
i: 7 j: 8
i: 8 j: 9
i: 9 j: 10
i: 10 j: 11
i: 11 j: 12

[Corey McGlone]

Originally posted by Akash:
Hi Folks
This runs fine. No systax error, no infinite loop also.

No, this is an infinite loop. Just because the output stops, doesn't mean that the loop ends. The fact is that the output only occurs when i <= 10. Also, i is only incremented while i <= 10.
Therefore, i will eventually become 11, and the loop will cycle endlessly, doing nothing. Try modifying the loop to this to see the infinite loop:

for(int i=0;i<=22 ; )  
{    
   if(i<= 10) 
   {      
      int j= 2 + i;      
      i++;      
      // /* let us know */ //      
      System.out.println("i: " + i + " j: " + j);   
   }
   System.out.println("Value of i: " + i);
}

Corey

[Akash Kumar]

Yes, Corey you are right, I was not looking closely.
Thanks a lot Corey,Swarna, and Malik.

[Corey McGlone]

Akash,
Let me again remind you of the JavaRanch Naming Policy. Please change your publicly displayed name to conform to this rule.
Thanks,
Corey

[Neil Laurance]

Corey
There seem to be a lot of reminders for people to change their names. Ever tried modifying the UBB cgi code to be more restrictive? Or would that invalidate your support contract

[srinivas bolloju]

Hi Neil,
you just said what i had in my mind.