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ArrayStoreException

Binu K Idicula
Ranch Hand

Joined: Jul 11, 2002
Posts: 99
see this ..Can you tell me why it causes Exception when object reference can hold any instance of its subclass.
Object obj = new String("test");
System.out.print(obj);
obj = new Integer(3);
System.out.print(obj);
prints test3
But in the case of array..
Object[] obj = new String[3];
obj[0] = new Integer(3);

causes an Array Store Exception ..
Can you explain it ??
William Brogden
Author and all-around good cowpoke
Rancher

Joined: Mar 22, 2000
Posts: 12823
    
    5
The real type of obj is String[] therefore you can only store a String in it. If you had created the reference stored in obj as:
Object[] obj = new Object[3], it would work.
Bill
Barry Gaunt
Ranch Hand

Joined: Aug 03, 2002
Posts: 7729
The real type of obj is String[] therefore you can only store a String in it

obj is referencing an array of three String references.
The code is trying to place a reference to an Integer into the first element of that array. As Bill said you cannot do that.
-Barry


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subject: ArrayStoreException