Overload, Override & more specific

[Alfred Kemety]

What will the following code do on compiling and running?

class A {
public long aMethod(int x) {
return 5 * x;
}
}
class Test extends A {
public long aMethod(long x) {
return 2 * x;
}
public static void main(String[] args) {
A a = new Test();
System.out.println(a.aMethod(2));
}
}

A- prints 5
B- prints 10
C- Compile Error because of ambiguity
D- Compile Error at declaration of aMethod in class Test
More important than what is why?

[Aniruddha Mukhopadhyay]

Answer obviously is B (will print 10). There is no case of method overriding here as methods have different argument type. As the argument is of type int, method:
public long aMethod(int x) {
return 5 * x;
}
will get called and output on screen will be 10.