Byte class

[Sridhar Srikanthan]

Hi all,
I found this question in Sreenivas Majji's Mock Exam question number 9.
The code is

  The following code will give
1:     Byte b1 = new Byte("127");
2:
3:     if(b1.toString() == b1.toString())
4:        System.out.println("True");
5:     else
6:        System.out.println("False");
A) Compilation error, toString() is not avialable for Byte.
B) Prints "True".
C) Prints "False".

The answer given is false. I checked it by running the answer given is correct. By viewing the question, my instincts led me to the option B(i,e B). Can someone explain how "==" and "equals()" work with Number class and its subclasses.
Thanks in advance
Sri

[Sarma Lolla]

When ever a toString() method is called a new String object is created wrapping the value of the byte and returned by the system. So the two string objects are never equal in this case.

[Sridhar Srikanthan]

Dear Sarma,
Thanks , I got it now
Sri