This week's book giveaways are in the iOS and Features new in Java 8 forums. We're giving away four copies each of Barcodes with iOS: Bringing together the digital and physical worlds and Core Java for the Impatient and have the authors on-line! See this thread and this one for details.
Hi Dan, Barry, I tried compiling with H h = new G(); h.m(); It is giving an error saying h is already defined in Class4. But I did find something in API documentation. http://java.sun.com/docs/books/tutorial/java/javaOO/override.html It says : Also, a subclass cannot override methods that are declared static in the superclass. In other words, a subclass cannot override a class method. A subclass can hide a static method in the superclass by declaring a static method in the subclass with the same signature as the static method in the superclass What does it mean when they say hiding a static method with the same signature. Pallavi
Static methods do not participate in polymorphism therefore they are hidden not overridden. This is one place where C# has Java beat. In C# you can't run static methods (which are class methods) with an object reference. Think about how we normally execute static methods. We don't do: H h = new H(); h.m(); we do: H.m(); Try this: the method that gets executed is determined at compile time for static methods. So when you do something like: H h = new G(); h.m(); Since h is a pointer to an H object, it is the static method of the H class that will be executed, not the static method of the G class. That is because at compile time the compiler has no idea that h is pointing to a G object. Static methods don't participate in polymorphism therefore they can't be overridden. They can only be hidden.