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The above code compiles fine but at runtime throws a ClassCastException. My query is, how is the compilation successful when the interface 'Test' and class 'Check' are no way related. Plz enlighten me on this. reshma
I agree with Tausif. The compiler assumes that the programmer knows what he/she is doing. At run time, the JVM finds that the cast is not legal and so an exception is thrown.
Dan Chisholm<br />SCJP 1.4<br /> <br /><a href="http://www.danchisholm.net/" target="_blank" rel="nofollow">Try my mock exam.</a>
Joined: Jul 02, 2002
Originally posted by sun par: ...if superclass implements an interface, the sub class automatically implements the interface.
Your statement is correct--"if superclass implements an interface, the sub class automatically implements the interface." However, the compiler knows all about the superclasses and is able to check any assumptions concerning a superclass. Remember, a class has an "extends" clause that specifies the superclass and an implements clause that specifies which interfaces are implemented. A class, however, does not have an "extended by" clause that specifies subclasses so the compiler does can not make any assumptions concerning subclasses. For example, the compiler can not know which interfaces might be implemented by a subclass.
Joined: Sep 17, 2002
Whats the difference 'Test t = (Test) c;' from the above code and 'String s = (String) new StringBuffer();'
Joined: Jul 02, 2002
Originally posted by Reshma Pai: Whats the difference 'Test t = (Test) c;' from the above code and 'String s = (String) new StringBuffer();'
The following is a quote from Section 5.5 of the Java Language Specification. "Some casts can be proven incorrect at compile time; such casts result in a compile-time error." A cast from StringBuffer to String would fall into the "can be proven incorrect at compile time" category. The compiler knows that a StringBuffer is not a subclass of String so the cast results in a compile time error. The compiler accepts the following cast Test t = (Test) c; Because Test is an interface and because a subclass of Check might implement Test. The following is another quote from Section 5.5 of the JLS. The remaining cases involve conversion between reference types. The detailed rules for compile-time correctness checking of a casting conversion of a value of compile-time reference type S (source) to a compile-time reference type T (target) are as follows: If S is a class type:
If T is a class type, then S and T must be related classes-that is, S and T must be the same class, or S a subclass of T, or T a subclass of S; otherwise a compile-time error occurs. If T is an interface type:
If S is not a final class (�8.1.1), then the cast is always correct at compile time (because even if S does not implement T, a subclass of S might).
If S is a final class (�8.1.1), then S must implement T, or a compile-time error occurs.
[ March 29, 2003: Message edited by: Dan Chisholm ]