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Hi, 1) Can, any of you explain how to convert big Hex decimal numbers to decimal. For ex, how will you convert 0xffffffc9 to decimal number. 2) byte b = 0; int i=0; Is there any short cut method is there to solve the below expression, b = (byte)(b + (b - (i = 0xffffffc9))) Thanks in Advance....

byte b = 0; int i=0; b = (byte)(b + (b - (i = 0xffffffc9))) 0xffffffc9 is going to be negative because the leftmost bit is 1. (f = 1111) so the number is going to be 111........11001001 because c = 1100 and 9 = 1001. Flip the bits and add 1. 000...........00110110 + 1 = 000....00110111 = -55 b = (byte)(b + (b - (-55))) b = (byte)(b + 55) b = (byte)(0 + 55) b = 55 I hope this helps

Narasimha - First here's a link that might help... http://www.coderanch.com/t/241326/java-programmer-SCJP/certification/Converting-Hexadecimal-literals The key points are: 1 - For anyone new to JavaRanch - the exam won't ask you to convert big hex or octal or binary numbers! 2 - The exam WILL ask you to understand how two's complement numbers are stored, and how the >>, >>>, << operators affect these two's complement numbers.

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