reference to m is ambiguous, both method m(B,B) in C and method m(A,C) in C match
1. Class C extends B => C IS_A B 2. Class B extends A => B IS_A A And because operator IS_A is transitief it follows from 1 and 2 that: C IS_A A We now know that object c can be passed to m(B,B) or m(A,C) Can (B,B) be passed on to (A,C): no, because B not IS_A C Can (A,C) be passed on to (B,B): no, because A not IS_A B Conclusion: m(B,B) is not more specific than m(A,C) BTW: all methods are in 1 class. If methods from a superclass class are overloaded the rules involve the classes as well. See other posting for this subject.
Joined: Jun 20, 2002
Thanks John,I got it . [ April 29, 2003: Message edited by: Veena Point ]
I’ve looked at a lot of different solutions, and in my humble opinion Aspose is the way to go. Here’s the link: http://aspose.com