This week's book giveaway is in the OCAJP 8 forum. We're giving away four copies of OCA Java SE 8 Programmer I Study Guide and have Edward Finegan & Robert Liguori on-line! See this thread for details.
Two ValuePair objects are equal if they contain the same valuer in their ints. (a == a and b == b) or (a == b and b == a) So the hashCode method must return an int so that equal objects have equal hashcodes. So a possible valid implementation might be a+b. Returning either a or b would not be valid.
I've recently read a chapter on this. My understanding with implementing hashCode() is that you take a look at the equals method and see which member variables are being used to compare the "value" of the instance of the class, and then create a hashCode implementation like: a+b. Now, I've been out of college for about 4 years, so my CS knowledge is not quite as sharp, but I was surpised to learn that a valid hashcode could also just be a constant, just "return 123;", but this would not be "efficient" because then every object would have the same hashcode, and I guess that this means when hashing your objects you won't get a good distribution in a Hashtable.