This week's book giveaway is in the JavaFX forum. We're giving away four copies of Introducing JavaFX 8 Programming and have Herbert Schildt on-line! See this thread for details.

The following question from dan's single topic exam: class D { static boolean m(double v) { return(v != v == Double.isNaN(v)); } public static void main (String args[]) { double d1 = Double.NaN; double d2 = Double.POSITIVE_INFINITY; double d3 = Double.MAX_VALUE; System.out.print(m(d1) + "," + m(d2) + "," + m(d3)); } } the ans is true, true true. I expected it to be false , true, true, because, in first case, v==Double.isNaN(v)is true and therefore, v!=v is flase. Pls clarify

I believe the answer to your question lies in the order in which these operands are evaluated. First, we evaluate v != v, which returns true because Double.NaN is not equal to Double.NaN. Next, we take that result (true) and compare it to the result of Double.isNaN(Double.NaN). That also returns true. Therefore, we finally check to see if true is equivalent to true, which, obviously, it is, and we get a final returned value of true. I hope that helps, Corey