Marcus Green exam question

[Zak Nixon]

  
What will happen when you attempt to compile and run the following code?
public class Sandys{
private int court;
public static void main(String argv[]){
        Sandys s = new Sandys(99);
        System.out.println(s.court);
        }
Sandys(int ballcount){
        court=ballcount;
        }
}

1) Compile time error, the variable court is defined as private
2) Compile time error, s is not initialized when the System.out method is called
3) Compilation and execution with no output
4) Compilation and run with an output of 99

I looked at the above line in Exam 3, Question 45 of Marcus Greens Mock tests. I was wondering one thing....
How can the static method main() access the court variable of s?
I tried placing a similar sample of code in my compiler, and was unable to compile it.
By the way, the answer given is 4.

Can someone explain?
Thanks
Zak Nixon

[Vivek Mongolu]

How can the static method main() access the court variable of s?

In the main method court variable is accessed thru the object which is fine but if you try to access the court variable without the object then it will give u compile time error saying that static method can only access static variables

Vivek