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assignment operator

jaysingh solanki
Greenhorn

Joined: Nov 11, 2003
Posts: 14
code:
class Test
{
int i=4;
i+=5;//line 1
public Test()
{
System.out.println(i);
}
public static void main(String arg[])
{
Test t=new Test();

}
}
My question is why line one gives compile time error
identifier exp.
Nathaniel Stoddard
Ranch Hand

Joined: May 29, 2003
Posts: 1258
"i" is an instance variable (since you don't see the keyword static anywhere).
Consequently, trying to initialize it at the static (class) level will result in an error. If you are trying to make "i" a class-level variable, use the static keyword and place their initiailization in a static { ... } block. Otherwise, "i" is an instance variables and need to be initialized in a constructor, not at Line 1 as it is now.


Nathaniel Stodard<br />SCJP, SCJD, SCWCD, SCBCD, SCDJWS, ICAD, ICSD, ICED
 
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subject: assignment operator