Overloading Methods

[Ivaturi Srinivas]

class X
{
public int process(int i)
{
System.out.println("Coming here into int");
return i;
}
public int process(byte i)
{
System.out.println("Coming here into byte");
return i;
}
public int process(short i)
{
System.out.println("Coming here into short");
return i;
}
}
public class ivaturi
{
public static void main(String args[])
{
X x = new X();
x.process(3);
}
}
If I run the above program I am getting called with int argument method. Why not byte or short. If I explicitly cast the x.process((byte)3) it is taking the byte argument method. Why the JVM impilicitly taking the int argument method when the method call is like this x.process(3);
Thanks for your time and help
Srinivas Ivaturi

[Vad Fogel]

3 is an int literal as far as JVM is concerned.